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This free AP Physics C: Mechanics practice exam tests the calculus the course is built on: integrating a time-dependent acceleration, reading stability from the derivative of a potential-energy function, locating the center of mass of a non-uniform rod, and deriving a moment of inertia from its definition. FRQ 1 sets up and solves the differential equation for a boat slowing under velocity-dependent drag; FRQ 2 combines moment of inertia, angular momentum conservation and energy for a putty-and-rod collision, where students lose marks by conserving linear momentum through a pivot.

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  1. Question 11 mark · Kinematics
    A particle moves along the x-axis with acceleration a(t)=6ta(t) = 6t (SI units). At t=0t = 0 it is at x=0x = 0 with velocity +2+2 m/s. Where is the particle at t=2t = 2 s?
    • A.
      x=8x = 8 m
    • B.
      x=12x = 12 m
    • C.
      x=14x = 14 m
    • D.
      x=16x = 16 m
  2. Question 21 mark · Newton's laws and drag
    A ball is thrown straight up and later returns to the launch height. Throughout the flight it experiences a drag force of magnitude bvbv opposing its motion. Let tupt_{up} be the time to reach the highest point and tdownt_{down} the time to fall back. Which statement is correct?
    • A.
      tup<tdownt_{up} < t_{down}, and the ball returns slower than it was launched
    • B.
      tup>tdownt_{up} > t_{down}, and the ball returns slower than it was launched
    • C.
      tup=tdownt_{up} = t_{down}, and the ball returns slower than it was launched
    • D.
      tup<tdownt_{up} < t_{down}, and the ball returns at the launch speed
  3. Question 31 mark · Work and energy
    A 2.0 kg object starts from rest at x=0x = 0 and moves along the x-axis under a single force F(x)=3x2F(x) = 3x^2, with FF in newtons and xx in metres. What is its speed at x=2.0x = 2.0 m?
    • A.
      2.0 m/s
    • B.
      222\sqrt{2} m/s
    • C.
      4.0 m/s
    • D.
      8.0 m/s
  4. Question 41 mark · Work and energy
    A particle moves along the x-axis with potential energy U(x)=x3−12xU(x) = x^3 - 12x, with UU in joules and xx in metres. At which position is the particle in STABLE equilibrium?
    • A.
      x=−2x = -2 m
    • B.
      x=0x = 0
    • C.
      x=2x = 2 m
    • D.
      x=4x = 4 m
  5. Question 51 mark · Center of mass
    A thin rod of length LL lies along the x-axis from x=0x = 0 to x=Lx = L. Its linear mass density increases linearly from zero at x=0x = 0: λ(x)=λ0x/L\lambda(x) = \lambda_0 x/L. Where is the center of mass of the rod?
    • A.
      x=L/3x = L/3
    • B.
      x=L/2x = L/2
    • C.
      x=2L/3x = 2L/3
    • D.
      x=3L/4x = 3L/4
  6. Question 61 mark · Momentum and collisions
    A block of mass mm moving at speed vv on a frictionless surface makes a head-on elastic collision with a block of mass 3m3m at rest. What is the speed of the 3m3m block after the collision?
    • A.
      v/4v/4
    • B.
      v/3v/3
    • C.
      v/2v/2
    • D.
      2v/32v/3
  7. Question 71 mark · Rotation
    A uniform solid sphere (I=25MR2I = \frac{2}{5}MR^2) rolls without slipping from rest down an incline, descending a vertical height hh. What is the speed of its center of mass at the bottom?
    • A.
      gh\sqrt{gh}
    • B.
      10gh/7\sqrt{10gh/7}
    • C.
      4gh/3\sqrt{4gh/3}
    • D.
      2gh\sqrt{2gh}
  8. Question 81 mark · Rotation
    A block of mass mm hangs from a light string wrapped around a uniform solid cylinder of mass MM and radius RR (I=12MR2I = \frac{1}{2}MR^2) that turns on a frictionless horizontal axle. The system is released from rest. What is the downward acceleration of the block?
    • A.
      gg
    • B.
      mgm+M\dfrac{mg}{m + M}
    • C.
      2mg2m+M\dfrac{2mg}{2m + M}
    • D.
      mgm+2M\dfrac{mg}{m + 2M}
  9. Question 91 mark · Angular momentum
    A 2.0 kg particle moves with constant velocity 4.0 m/s in the +x+x direction along the line y=3.0y = 3.0 m. Its angular momentum about the origin:
    • A.
      has magnitude 24 kg⋅m2/s24\ \text{kg}\cdot\text{m}^2\text{/s} and is constant
    • B.
      has magnitude 24 kg⋅m2/s24\ \text{kg}\cdot\text{m}^2\text{/s} and increases as the particle moves away from the origin
    • C.
      is zero, because the particle moves in a straight line
    • D.
      has magnitude 8.0 kg⋅m2/s8.0\ \text{kg}\cdot\text{m}^2\text{/s} and is constant
  10. Question 101 mark · Oscillations
    A 0.50 kg object on a frictionless surface experiences a net force F=−32xF = -32x, with FF in newtons and xx in metres. What is the period of its oscillation?
    • A.
      π/8\pi/8 s
    • B.
      π/4\pi/4 s
    • C.
      π/2\pi/2 s
    • D.
      π\pi s
  11. Question 111 mark · Gravitation
    A satellite of mass mm is in a circular orbit of radius rr around a planet of mass MM. What minimum work must be done on the satellite to move it to a circular orbit of radius 2r2r?
    • A.
      GMm8r\dfrac{GMm}{8r}
    • B.
      GMm4r\dfrac{GMm}{4r}
    • C.
      GMm2r\dfrac{GMm}{2r}
    • D.
      GMmr\dfrac{GMm}{r}
  12. Question 121 mark · Gravitation
    The escape speed from the surface of Earth is about 11.2 km/s. A planet has twice Earth's mass and twice Earth's radius. What is the escape speed from its surface?
    • A.
      5.6 km/s
    • B.
      7.9 km/s
    • C.
      11.2 km/s
    • D.
      22.4 km/s
  13. Question 1312 marks · Newton's laws and drag
    Drag. A motorboat of mass m=200m = 200 kg is moving at v0=6.0v_0 = 6.0 m/s across still water when its engine is shut off at t=0t = 0. The water exerts a resistive force on the hull of magnitude bvbv, directed opposite to the velocity, where b=40b = 40 kg/s. Ignore all other horizontal forces.
    (a)
    Write Newton's second law for the boat as a differential equation for its speed v(t)v(t), and give the numerical value of the constant that appears.
    [2]
    (b)
    Solve the differential equation to obtain v(t)v(t), showing the separation of variables and the use of the initial condition.
    [3]
    (c)
    Calculate the time at which the boat's speed has fallen to half its initial value.
    [2]
    (d)
    Calculate the total distance the boat travels after the engine is shut off (that is, as t→∞t \to \infty).
    [3]
    (e)
    Suppose instead that the resistive force had magnitude cv2cv^2, where cc is a positive constant. Using the differential equation (you need not solve for v(t)v(t)), argue whether the boat would travel a finite or an unbounded distance before its speed reaches zero.
    [2]
  14. Question 1412 marks · Rotation
    Rod and putty. A thin uniform rod of mass M=1.5M = 1.5 kg and length L=1.0L = 1.0 m hangs at rest from a frictionless pivot at its upper end and is free to swing in a vertical plane. A lump of putty of mass m=0.50m = 0.50 kg moving horizontally at v0=4.0v_0 = 4.0 m/s strikes the lower end of the rod and sticks to it. Use g=9.8 m/s2g = 9.8\ \text{m/s}^2.
    (a)
    Starting from I=∫r2 dmI = \int r^2\,dm, derive the rotational inertia of the rod about the pivot. Then calculate the total rotational inertia of the rod-and-putty system about the pivot after the collision.
    [3]
    (b)
    Calculate the angular speed of the rod-and-putty system immediately after the collision.
    [3]
    (c)
    Explain why angular momentum about the pivot is conserved during the collision, but the linear momentum of the rod-and-putty system is not.
    [2]
    (d)
    Calculate the maximum angle, measured from the vertical, through which the rod swings after the collision.
    [4]

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AP Physics C: Mechanics exam tips

  • Write the differential equation before solving it: "m dv/dt = -bv" earns the setup point even if the integration goes wrong, and separating variables with correct limits earns the next.
  • When a force depends on position, work is an integral, not force times distance: integrate F(x) dx between the given limits and show the antiderivative.
  • With a pivot or axle present, linear momentum is NOT conserved during a collision (the pivot pushes); use angular momentum about the pivot and say why the pivot force exerts no torque there.
  • Derive, do not quote: when asked for a moment of inertia "using calculus", start from the definition (I is the integral of r squared dm) and write dm in terms of a linear or area density before integrating.

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